I knew this would start this whole silly argument all over again. We've had numerous photographs and even a chemist weigh in on this debunking the gold base coat theory. There was no gold base coat this is just how the red oxidizes. Can we finally put this horse down?
Silly argument? I think not. A silly argument would be saying that Schwinn installed a cheesy Wald reflector on the Phantom, their flagship bike. Schwinnlax did not debunk the gold base, he simply said it was possible that red could fade to gold.
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Presumably the original paint is still there under the decals (chain guard, seat tube). That being the case, the original red paint is still there under the decals, and not somehow scraped or worn off. Unless the red paint faded to clear revealing a gold coat underneath, it has to be the red paint that faded to gold. Just using logic here...
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Also, paint oxidation is completely different than the paint colorant fading. You can buff out oxidized paint but you can't buff out loss of color. Years ago I painted my 1967 Chevelle Marina Blue Metallic with a single stage enamel. Before I sold that car the blue pigment
completely faded out and the car was silver, which was the silver metallic particles used in the paint. GM's old metallic paint in the late 50's into the 60's not only oxidized quickly here in Arizona, the paint pigment also faded out and the colors never turned a different color, they just faded out. Over the years I've seen hundreds of these cars where the paint colorant fades completely away.
Again, "numerous photographs." Here is faded red English bike with a red candy shot over a silver base. I don't see one trace of the red turning to gold. Why is that?
And here is a red Schwinn where the red faded out and turned to gold? Naw, that's a gold base.
Can you prove your theory that Schwinn's red candy fades to gold? Saying Schwinn never used a gold base is just your belief, and these two pictures sure would indicate that Schwinn did in fact use a gold base during this time, so the horse is still running.